(2x^2-23x-12)/12=25

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Solution for (2x^2-23x-12)/12=25 equation:


x in (-oo:+oo)

(2*x^2-(23*x)-12)/12 = 25 // - 25

(2*x^2-(23*x)-12)/12-25 = 0

(2*x^2-23*x-12)/12-25 = 0

(2*x^2-23*x-12)/12+(-25*12)/12 = 0

2*x^2-23*x-25*12-12 = 0

2*x^2-23*x-312 = 0

2*x^2-23*x-312 = 0

2*x^2-23*x-312 = 0

DELTA = (-23)^2-(-312*2*4)

DELTA = 3025

DELTA > 0

x = (3025^(1/2)+23)/(2*2) or x = (23-3025^(1/2))/(2*2)

x = 39/2 or x = -8

(x+8)*(x-39/2) = 0

((x+8)*(x-39/2))/12 = 0

((x+8)*(x-39/2))/12 = 0 // * 12

(x+8)*(x-39/2) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-39/2 )

x-39/2 = 0 // + 39/2

x = 39/2

x in { -8, 39/2 }

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